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10x^2-15x-17/5=0
We multiply all the terms by the denominator
10x^2*5-15x*5-17=0
Wy multiply elements
50x^2-75x-17=0
a = 50; b = -75; c = -17;
Δ = b2-4ac
Δ = -752-4·50·(-17)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9025}=95$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-95}{2*50}=\frac{-20}{100} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+95}{2*50}=\frac{170}{100} =1+7/10 $
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